Question: Payouts in Rebuy-Tournaments
Posted: Tue Jan 23, 2024 12:02 pm
Hi Kent, hi all,
I've got a question regarding the payouts in rebuy tournaments.
Given: Tournament with 6 players A,B,C,D,E and F. Buyin 10$ each. Unlimited Rebuys allowed.
With these specs we start with 60$ in our prize pool.
Let us say the first 3 players get payouts (50% = 30$, 30% = 18$, 20% = 12$)
Players E and F drop out in the last places without rebuys. Player D rebuys for another 10$, increasing the prize pool to 70$.
Player D drops out in 4th place. No payout for 4th place.
Player C drops out in 3rd place, getting 20% of now 70$ (= 14$). The remaining prize pool would bei 56$.
Player A and B both rebuy for 10$, increasing the remaining prize pool to 76$. (Or the original prize pool to 90$ ??)
Player B finishes in 2nd place. Will he take 30% of the remaining 76$ (=22,80$), or 30% of 90$ (=27$)?
Would Player C's payout get recalculated to 20% of 90$ (=18$). He would get an additional 4$ after the tournament's end. Is that correct?
Player A could get 50% of the remaining 76$ (=38$) in comparison to 50% of 90$ (=45$).
I don't really get it. Can someone, preferrably Kent, explain, please?
No matter how I count, my payout sum is always less than 90$ if player C doesn't get the extra 4$ after the final hand.
Thanks for taking the time to read and explain.
I've got a question regarding the payouts in rebuy tournaments.
Given: Tournament with 6 players A,B,C,D,E and F. Buyin 10$ each. Unlimited Rebuys allowed.
With these specs we start with 60$ in our prize pool.
Let us say the first 3 players get payouts (50% = 30$, 30% = 18$, 20% = 12$)
Players E and F drop out in the last places without rebuys. Player D rebuys for another 10$, increasing the prize pool to 70$.
Player D drops out in 4th place. No payout for 4th place.
Player C drops out in 3rd place, getting 20% of now 70$ (= 14$). The remaining prize pool would bei 56$.
Player A and B both rebuy for 10$, increasing the remaining prize pool to 76$. (Or the original prize pool to 90$ ??)
Player B finishes in 2nd place. Will he take 30% of the remaining 76$ (=22,80$), or 30% of 90$ (=27$)?
Would Player C's payout get recalculated to 20% of 90$ (=18$). He would get an additional 4$ after the tournament's end. Is that correct?
Player A could get 50% of the remaining 76$ (=38$) in comparison to 50% of 90$ (=45$).
I don't really get it. Can someone, preferrably Kent, explain, please?
No matter how I count, my payout sum is always less than 90$ if player C doesn't get the extra 4$ after the final hand.
Thanks for taking the time to read and explain.